Refer to the exhibit. You are the network administrator responsible for the NProuter, the 10.1.1.1 router, and the 10.1.1.2 router. What can you determine about the OSPF operations from the debug output?

NProuter#debug ip ospf events OSPF events debugging is on NProuter# 00:02:03: OSPF: Rev hello from 172.16.1.1 area 0 from Serial0/0 10.1.1.1 00:02:03: OSPF: Mismatched hello parameter from 10.1.1.1 00:02:03: OSPF: Dead R 120 C 10, Hello R 30 C 30  00:02:26: OSPF’ Rcv hello from 192.168.1.2 area 0 from Serial0/0 10.1.1.2  00:02:26: OSPF: Mismatched hello parameters from 10.1.1.2  00:02:26: OSPF: Dead R 120 C 10, Hello R 30 C 30

A. The NProuter has two OSPF neighbors in the “Full” adjacency state.
B. The NProuter serial0/0 interface has the OSPF dead timer set to 10 seconds.
C. The NProuter serial0/0 interface has been configured with an OSPF network type of “point-to-point”.
D. The 10.1.1.1 and 10.1.1.2 routers are not using the default OSPF dead and hello timers setting.
E. The “Mismatched” error is caused by the expiration of the OSPF timers.

Answer: B

Explanation

First we should understand clearly about the line

Dead R 120 C 10, Hello R 30 C 30

The “R” here means “Received” and “C” means “Configured”. In other words, “Dead R” is the Dead Timer Received from the neighbor and the “Dead C” is the Dead Timer of the local router.

Therefore in this case “Dead R 120 C 10″ means the Death Timer of the neighbor is 120 seconds while the local Dead Timer is 10 seconds, which causes a mismatch. Also we can learn that the local OSPF dead timer is set to 10 seconds -> B is correct.

For your information, by default, OSPF uses a 10-second hello timer and 40-second hold timer on broadcast and point-to-point links, and a 30-second hello timer and 120-second hold timer for all other network types. So we can’t confirm answer D is correct or not.

Question 2

You have just completed an OSPF implementation. While executing your verification plan, you determine that R1 is not able to establish full OSPF adjacency with R2. The show ip ospf neighbor command output on R1 shows that R2 is stuck in the INIT state.

What could be the cause of this problem?

A. DR and BDR election errors between R1 and R2.
B. The R2 router has not received the OSPF hello packets from the R1 router.
C. Mismatched interface maximum transmission unit (MTU) configuration between the R1 and R2. 
D. Mismatched OSPF hello interval configuration between the R1 and R2.
E. Corrupted LSAs exchanges between the R1 and R2.

Answer: B

Explanation

When a router receives an OSPF Hello from a neighbor, it sends the Hello packet by including that neighbor’s router ID in the Hello packet. If the neighbor does not receive this packet (means that it doesn’t see itself in this packet), it will be stuck in INIT state. INIT state can be understood as a one-way Hello. An example of a router stuck in INIT state is shown below:

Question 3

Refer to the exhibit. You have completed an OSPF implementation, and you are verifying OSPF operation. You notice that router A and router B are stuck in the two-way state. From the show ip ospf interface command output, what is the cause of this issue?

A. All OSPF implementations must have at least one interface in area 0.
B. You are attempting to run in the broadcast mode over an NBMA interface.
C. Both routers are configured to function as a BDR; therefore, there is no DR router.
D. Someone has changed the OSPF router ID; therefore you must clear the OSPF process. 
E. The OSPF priority is set to 0 on both routers; therefore neither can become the DR.

Answer: E

Explanation

When OSPF adjacency is formed, a router goes through several state changes before it becomes fully adjacent with its neighbor. The states are Down, Attempt, Init, 2-Way, Exstart, Exchange, Loading, and Full.

An OSPF neighbor reaches the 2-way state when bidirectional communication is established (each router has seen the other’s hello packet). This is the beginning of an OSPF adjacency. On broadcast media and non-broadcast multiaccess networks, the DR and BDR are elected in this state. But the priority on both routers are 0 so no DR and BDR are elected -> These routers stay in the 2-way state.

(Reference and a good resource of OSPF Neighbor states: http://www.cisco.com/en/US/tech/tk365/technologies_tech_note09186a0080093f0e.shtml)

Question 4

You have completed an OSPF implementation, and you are verifying OSPF operation. During this verification, you notice that the OSPF route of 172.16.10.0 is repeatedly appearing and disappearing from the routing table. Further investigation finds that the OSPF CPU utilization is very high and the routers are constantly performing SPF calculations. You determine that 172.16.20.2 is the source of the 172.16.10.0 route. Using the show ip ospf database router 172.16.20.1 command, you notice that when this show command is performed repeatedly, the contents of the LSA change every few seconds.

What could be the cause of this problem?

A. OSPF authentication errors between some of the routers.
B. Two routers have the same OSPF router ID.
C. Issues with mistuned OSPF timers.
D. OSPF LSA pacing issues between some of the routers.
E. OSPF neighbor adjacency problems between some of the routers.

Answer: B

Question 5

The maximum number of routers per OSPF area typically depends on which three factors? (Choose three)

A. the kind of OSPF areas being implemented 
B. the number of external LSAs in the network
C. the number of DRs and BDRs in the areas
D. the number of virtual links in the areas 
E. how well the areas can be summarized 
F. the use of LSA filters

Answer: A B E

Question 6

When verifying OSPF virtual link problems, which is an important item to check on the two transit OSPF routers?

A. OSPF process ID
B. OSPF router ID
C. OSPF network type
D. OSPF memory usage
E. OSPF CPU utilization
F. OSPF stub area configurations

Answer: B

Explanation

The OSPF router IDs of the two transit OSPF routers are used to form the virtual link (with the area area-id virtual-link neighbor-router-id command) so it is an important item to check -> B is correct.

Question 7

The administrator wants to verify the current state of the OSPF database loading process.
Which show command should the administrator use?

A. show ip ospf [process-id] interface
B. show ip ospf neighbor
C. show ip ospf [process-id]
D. show ip ospf [process-id area-id] database

Answer: B

Explanation

The “show ip ospf neighbor” command can be used to view the current state of the OSPF database loading process. In the output below we can see router 2.2.2.2 is in 2way state, router 3.3.3.3 is elected as the BDR & router 4.4.4.4 is the BR.

Question 8

Which two statements about route redistribution when implementing OSPF are true? (Choose two)

A. Routes learned using any IP routing protocol can only be redistributed into non IP routing protocols.
B. OSPF can import routes learned using EIGRP, RIP, and IS-IS.
C. OSPF routes cannot be exported into EIGRP, RIP, and IS-IS.
D. At the interdomain level, OSPF cannot import routes learned using BGP.
E. OSPF routes can be exported into BGP.

Answer: B E

Question 9

An administrator types in the command router ospf 1 and receives the error message: “OSPF process 1 cannot start.” (Output is omitted.)
What should be done to correctly set up OSPF?

A. Ensure that an interface has been configured with an IP address.
B. Ensure that an interface has been configured with an IP address and is up.
C. Ensure that IP classless is enabled.
D. Ensure that the interfaces can ping their directly connected neighbors.

Answer: B

Explanation

OSPF can be only started when there is at least one interface up and configured with an IP address on the router.

Question 10

Which three are advantages to creating multiple areas in OSPF? (Choose three)

A. less frequent SPF calculations
B. fewer hello packets
C. smaller routing tables
D. reduced LSU overhead 
E. fewer adjacencies needed

Answer: A C D

Explanation

OSPF routers within an area only need to know about other routers within their own area, not outside their area, and all OSPF routers within a given area share the same link state database. This keeps the routing tables small enough to prevent processing bottlenecks from occurring -> C is correct.

Also SPF only needs to calculate paths to routers within that area -> A is correct.

If a router receives an LSA with old information then it will send a LSU to the sender to update the sender with the newer information. The Link State Update (LSU) holds the LSAs. Instead of sending multiple LSUs the ABR / ASBR summarizes a route and sends only one LSU-> D is correct.

Note: The LSA has a 30 minute timer that causes the router to send an LSU to everyone on the network once it ages out.

Into which two types of areas would an area border router (ABR) inject a default route? (Choose two)

A. the autonomous system of a different interior gateway protocol (IGP)
B. area 0
C. totally stubby
D. NSSA
E. stub
F. the autonomous system of an exterior gateway protocol (EGP)

Answer: C E

Explanation

Both stub area & totally stubby area allow an ABR to inject a default route. The main difference between these 2 types of areas is:

+ Stub area replaces LSA Type 5 (External LSA – created by an ASBR to advertise network from another autonomous system) with a default route 
+ Totally stubby area replaces both LSA Type 5 and LSA Type 3 (Summary LSA – created by an ABR to advertise network from other areas, but still within the AS, sometimes called interarea routes) with a default route.

Below summarizes the LSA Types allowed and not allowed in area types:

Area Type	Type 1 & 2 (within area)	Type 3 (from other areas)	Type 4	Type 5	Type 7
Standard & backbone	Yes	Yes	Yes	Yes	No
Stub	Yes	Yes	No	No	No
Totally stubby	Yes	No	No	No	No
NSSA	Yes	Yes	No	No	Yes
Totally stubby NSSA	Yes	No	No	No	Yes

Question 2

Which three restrictions apply to OSPF stub areas? (Choose three)

A. No virtual links are allowed.
B. The area cannot be a backbone area.
C. Redistribution is not allowed unless the packet is changed to a type 7 packet.
D. The area has no more than 10 routers.
E. No autonomous system border routers are allowed.
F. Interarea routes are suppressed.

Answer: A B E

Question 3

Refer to the partial configurations in the exhibit. What address is utilized for DR and BDR identification on Router1?

Router1#show run **** output omitted ****** interface serial1/1 ipv6 address 2001:410:FFFE:1::64/64  ipv6 ospf 100 area 0 ! interface serial2/0 ipv6 address 3FFF:B00:FFFF:1::2/64  ipv6 ospf 100 area 0 ! ipv6 router ospf  router-id 10.1.1.3

A. the serial 1/1 address
B. the serial 2/0 address
C. a randomly generated internal address
D. the configured router-id address

Answer: D

Explanation

In OSPFv3 and OSPF version 2, the router uses the 32-bit IPv4 address to select the router ID for an OSPF process. The router ID selection process for OSPFv3 is described below (same as OSPF version 2):

1. The router ID is used if explicitly configured with the router-id command.
2. Otherwise, the highest IPv4 loopback address is used.
3. Otherwise, the highest active IPv4 address.
4. Otherwise, the router ID must be explicitly configured.

In this case the router ID 10.1.1.3 is explicitly configured -> D is correct.

Question 4

By default, which statement is correct regarding the redistribution of routes from other routing protocols into OSPF?

A. They will appear in the OSPF routing table as type E1 routes.
B. They will appear in the OSPF routing table as type E2 routes.
C. Summarized routes are not accepted.
D. All imported routes will be automatically summarized when possible.
E. Only routes with lower administrative distances will be imported.

Answer: B

Explanation

Type E1 external routes calculate the cost by adding the external cost to the internal cost of each link that the packet crosses while the external cost of E2 packet routes is always the external cost only. E2 is useful if you do not want internal routing to determine the path. E1 is useful when internal routing should be included in path selection. E2 is the default external metric when redistributing routes from other routing protocols into OSPF -> B is correct.

Question 5

Which statement is true about OSPF Network LSAs?

A. They are originated by every router in the OSPF network. They include all routers on the link, interfaces, the cost of the link, and any known neighbor on the link.
B. They are originated by the DR on every multi-access network. They include all attached routers including the DR itself.
C. They are originated by Area Border Routers and are sent into a single area to advertise destinations outside that area.
D. They are originated by Area Border Router and are sent into a single area to advertise an Autonomous System Border Router.

Answer: B

Explanation

Popular LSA Types are listed below:

LSA Type	Description	Details
1	Router LSA	Generated by all routers in an area to describe their directly attached links
2	Network LSA	Advertised by the DR of the broadcast network (does not cross ABR)
3	Summary LSA	Advertised by the ABR of originating area
4	Summary LSA	Generated by the ABR of the originating area to advertise an ASBR to all other areas in the autonomous system
5	AS external LSA	Used by the ASBR to advertise networks from other autonomous systems
7	Defined for NSSAs	Generated by an ASBR inside a Not-so-stubby area (NSSA) to describe routes redistributed into the NSSA

Question 6

Refer to the exhibit. OSPF is configured on all routers in the network. On the basis of the show ip ospf neighbor output, what prevents R1 from establishing a full adjacency with R2?

A. Router R1 will only establish full adjacency with the DR and BDR on broadcast multiaccess networks. 
B. Router R2 has been elected as a DR for the broadcast multiaccess network in OSPF area 
C. Routers R1 and R2 are configured as stub routers for OSPF area 1 and OSPF area 2.
D. Router R1 and R2 are configured for a virtual link between OSPF area 1 and OSPF area 2.
E. The Hello parameters on routers R1 and R2 do not match.

Answer: A

Explanation

From the output, we learn that R4 is the DR and R3 is the BDR so other routers will only establish full adjacency with these routers. All other routers have the two-way adjacency established -> A is correct.

Question 7

Refer to the exhibit. On the basis of the configuration provided, how are the Hello packets sent by R2 handled by R5 in OSPF area 5?

A. The Hello packets will be exchanged and adjacency will be established between routers R2 and R5.
B. The Hello packets will be exchanged but the routers R2 and R5 will become neighbors only.
C. The Hello packets will be dropped and no adjacency will be established between routers R2 and R5.
D. The Hello packets will be dropped but the routers R2 and R5 will become neighbors.

Answer: C

Explanation

Recall that in OSPF, two routers will become neighbors when they agree on the following: Area-id, Authentication, Hello and Dead Intervals, Stub area flag.

We must specify Area 5 as a stub area on the ABR (R2) and all the routers in that area (R5 in this case). But from the output, we learn that only R3 has been configured as a stub for Area 5. This will drop down the neighbor relationship between R3 and R5 because the stub flag is not matched in the Hello packets of these routers.

Question 8

When an OSPF design is planned, which implementation can help a router not have memory resource issues?

A. Have a backbone area (area 0) with 40 routers and use default routes to reach external destinations.
B. Have a backbone area (area 0) with 4 routers and 30,000 external routes injected into OSPF.
C. Have less OSPF areas to reduce the need for interarea route summarizations.
D. Have multiple OSPF processes on each OSPF router. Example, router ospf 1, router ospf 2

Answer: A

Question 9

When verifying the OSPF link state database, which type of LSAs should you expect to see within the different OSPF area types? (Choose three)

A. All OSPF routers in stubby areas can have type 3 LSAs in their database.
B. All OSPF routers in stubby areas can have type 7 LSAs in their database.
C. All OSPF routers in totally stubby areas can have type 3 LSAs in their database.
D. All OSPF routers in totally stubby areas can have type 7 LSAs in their database.
E. All OSPF routers in NSSA areas can have type 3 LSAs in their database.
F. All OSPF routers in NSSA areas can have type 7 LSAs in their database.

Answer: A E F

Explanation

Below summarizes the LSA Types allowed and not allowed in area types:

Area Type	Type 1 & 2 (within area)	Type 3 (from other areas)	Type 4	Type 5	Type 7
Standard & backbone	Yes	Yes	Yes	Yes	No
Stub	Yes	Yes	No	No	No
Totally stubby	Yes	No	No	No	No
NSSA	Yes	Yes	No	No	Yes
Totally stubby NSSA	Yes	No	No	No	Yes

Popular LSA Types are listed below:

LSA Type	Description	Details
1	Router LSA	Generated by all routers in an area to describe their directly attached links
2	Network LSA	Advertised by the DR of the broadcast network (does not cross ABR)
3	Summary LSA	Advertised by the ABR of originating area
4	Summary LSA	Generated by the ABR of the originating area to advertise an ASBR to all other areas in the autonomous system
5	AS external LSA	Used by the ASBR to advertise networks from other autonomous systems
7	Defined for NSSAs	Generated by an ASBR inside a Not-so-stubby area (NSSA) to describe routes redistributed into the NSSA

Question 10

You are troubleshooting an OSPF problem where external routes are not showing up in the OSPF database. Which two options are valid checks that should be performed first to verify proper OSPF operation? (Choose two)

A. Are the ASBRs trying to redistribute the external routes into a totally stubby area?
B. Are the ABRs configured with stubby areas?
C. Is the subnets keyword being used with the redistribution command?
D. Is backbone area (area 0) contiguous?
E. Is the CPU utilization of the routers high?

Answer: A C

Explanation

A totally stubby stubby area cannot have an ASBR so it will discard this type of LSA (LSA Type 5) -> A is a valid check.

Each stubby area needs an ABR to communicate with other areas so it is normal -> B is not a valid check.

When pulling routes into OSPF, we need to use the keyword “subnets” so that subnets will be redistributed too. For example, if we redistribute these EIGRP routes into OSPF:

+ 10.0.0.0/8
+ 10.10.0.0/16
+ 10.10.1.0/24

without the keyword “subnets”

router ospf 1
redistribute eigrp 1

Then only 10.0.0.0/8 network will be redistributed because other routes are not classful routes, they are subnets. To redistribute subnets we must use the keyword “subnets”

router ospf 1
redistribute eigrp 1 subnets

-> C is a valid check.

We don’t need to care if area 0 is contiguous or not -> D is not a valid check.

CPU utilization cannot be the cause for this problem -> E is not a valid check.

Question 1

An administrator Pipes in the command router ospf 1 and receives the error message: “OSPF process 1 cannot start.” (Output is omitted.) What should be done to correctly set up OSPF?

A – Ensure that an interface has been configured with an IP address

B – Ensure that an interface has been configured with an IP address and is up
C – Ensure that IP classless is enabled
D – Ensure that the interfaces can ping their directly connected neighbors

Answer: B

Question 2

During a recent OSPF election among three routers. RTA was elected the DR and RTB was elected the BDR, as seen in the graphic. Assume that RTA fails, and that RTB takes the place of the DR while RTC becomes the new BDR. What will happen when RTA comes back online?

A – RTA will take the place of DR immediately upon establishing its adjacencie
B – RTA will take the place of DR only if RTB fails
C – RTA will take the place of DR only if both RTB and RTC fail
D – A new election will take place establishing an all new DR and BDR based on configured priority levels and MAC addresses

Answer: C

Question 3

Refer to the exhibit. During the process of configuring a virtual link to connect area 2 with the backbone area, the network administrator received this console message on R3:
*Mar 1 00:25:01.084: %OSPF-4-ERRRCV: Received invalid packet: mismatch area ID, from backbone area must be virtual link but not found from 20.20.20.1, Serial 0

How should the virtual link be configured on the OSPF routers to establish full connectivity between the areas?

A – R1(config-router)# area 1 virtual-link 30.30.30.3 
R3(config-router)# area 1 virtual-link 20.20.20.1
B – R1(config-router)# area 1 virtual-link 20.20.20.2 
R3(config-router)# area 1 virtual-link 30.30.30.2
C – R1(config-router)# area 0 virtual-link 1.1.1.1
R3(config-router)# area 2 virtual-link 3.3.3.3
D – R1(config-router)# area 1 virtual-link 3.3.3.3 
R3(config-router)# area 1 virtual-link 1.1.1.1
E – R1(config-router)# area 1 virtual-link 2.2.2.2 
R3(config-router)# area 1 virtual-link 2.2.2.2

Answer: D

Explanation

When designing a multi-area OSPF network, all areas should be connected to the backbone area. However, there may be instances when an area will need to cross another area to reach the backbone area like area 2 in this case. A virtual link has the following two requirements:

+ It must be established between two routers that share a common area and are both ABRs. 
+ One of these two routers must be connected to the backbone.

In this case, two routers that satisfy the above requirements are R1 and R3. The syntax for creating a virtual link across an area is:

area area-id virtual-link neighbor-router-id

The area-id is the number of the transit area, in this example Area 1 and neighbor-router-id is the IP address of the highest loopback interface configured or can be manually set on the neighboring router.

Question 4

As shown in the exhibit ,OSPF is configured over a Frame Relay network. All PVCs are active. However, P4S1 and P4S3 fail to see all OSPF routes in their routing tables. The show ip ospf neighbor command executed on P4S2 displays the state of the neighbors. In order to fix the problem , what should be done?

A – The neighbor command should be configured under the OSPF routing process on all routers
B – The ip ospf network broadcast command should be configured on each Frame Relay interface
C – The ip ospf network non-broadcast command should be configured on each Frame Relay interface
D – The ip ospf priority value on the spoke routers should be set to 0

Answer: D

Explanation

In an NBMA network topology, neighbors are not discovered automatically. OSPF tries to elect a DR and a BDR due to the multi-access nature of the network, but the election fails since neighbors are not discovered because NBMA environment doesn’t forward broadcast and multicast packets. Neighbors must be configured manually to overcome these problems.

Also, additional configuration is necessary in a hub and spoke topology to make sure that the hub routers, which have connectivity with every other spoke router, are elected as the DR and BDR. You must set the spoke interfaces to an OSPF priority of zero, this ensures that the spokes will not become the DR or BDR.

Question 5

The following exhibit shows ipv6 route output. What would the metric be for a summary route that summarizes all three OSPFv3 routes displayed?

A – 160
B – 140
C – 120
D – 100

Answer: D

Explanation

The cost of the summarized routes is the highest cost of the routes being summarized. In fact, in the old RFC 1583 standard, the cost of the summary route was the cost of the lowest metric. But when OSPF was updated in RFC 2178 and RFC 2328, the summary route should have the same cost as the highest-cost summarized route. In this case, the highest-cost is 100 according to the second entry.

Question 6

Study the exhibit below carefully. In order to summarize all routes from area 0 to area 1, what must be configured on the router?

A – area 0 range 172.16.96.0 255.255.224.0
B – area 1 range 172.16.96.0 255.255.224.0
C – area 1 range 172.16.96.0 255.255.0.0 
D – area 0 range 172.16.96.0 255.255.255.0

Answer: A

Question

Refer to the exhibit. BigBids Incorporated is a worldwide auction provider. The network uses EIGRP as its routing protocol throughout the corporation. The network administrator does not understand the convergence of EIGRP. Using the output of the show ip eigrp topology all-linkscommand, answer the administrator’s questions.

Question 1

Which two networks does the Core1 device have feasible successors for? (Choose two)

A – 172.17.0.0/30
B – 172.17.1.0/24
C – 172.17.2.0/24
D – 172.17.3.0/25
E – 172.17.3.128/25
F – 10.140.0.0/24

Answer: A F

Explanation

To understand the output of the “show ip eigrp topology all-links command” command, let’s analyze an entry (we choose the second entry because it is better for demonstration than the first one)

The first line tells us there is only 1 successor for the path to 10.140.0.0/24 network but there are 2 lines below. So we can deduce that one line is used for successor and the other is used for another route to that network. Each of these two lines has 2 parameters: the first one (“156160″ or “157720″) is the Feasible Distance (FD) and the second (“128256″ or “155160″) is the Advertised Distance (AD) of that route.

The next thing we want to know is: if the route via 172.17.10.2 (the last line) would become the feasible successor for the 10.140.0.0/24 network. To figure out, we have to compare the Advertised Distance of that route with the Feasible Distance of the successor’s route, if AD < FD then it will become the feasible successor. In this case, because AD (155160) < FD (156160) so it will become the feasible successor. Therefore we can conclude the network 10.140.0.0/24 has 1 feasible successor.

After understanding the output, let’s have a look at the entire output:

Because the question asks about feasible successor so we just need to focus on entries which have more paths than the number of successor. In this case, we find 3 entries that are in blue boxes because they have only 1 successor but has 2 paths, so the last path can be the feasible successor.

By comparing the value of AD (of that route) with the FD (of successor’s route) we figure out there are 2 entries will have the feasible successor: the first and the second entry. The third entry has AD = FD (30720) so we eliminate it.

Question 2

Which three EIGRP routes will be installed for the 172.17.3.128/25 and 172.17.2.0/24 networks? (Choose three)

A – 172.17.3.128.25 [90/28160] via 172.17.1 2, 01:26:35, FastEthernet0/2
B – 172.17.3.128/25 [90/30720] via 172.17.3.2, 01:26:35. FastEthemet0/3
C – 172.17.3.128/25 [90/30720] via 172.17.10.2, 01:26:35. FastEthernet0/1
D – 172.17.2.0/24 [90/30720] via 172.17.10.2, 02:10:11, FastEthernet0/1
E – 172.17.2.0/24 [90/28160] via 172.17.10.2, 02:10:11. FastEthernet0/1
F – 172.17.2.0/24 [90/33280] via 172.17.3.2, 02:10:11. FastEthernet0/3

Answer: B C D

Explanation

First indicate the positions of these networks:

Network 172.17.3.128/25 has 2 successors, therefore the two paths below are both successors.

Network 172.17.2.0/24 has only 1 successor, therefore the path lies right under it is the successor.

Question 3

Which three networks is the router at 172.17.10.2 directly connected to? (Choose three)

A – 172.17.0.0/30
B – 172.17.1.0/24
C – 172.17.2.0/24
D – 172.17.3.0/25
E – 172.17.3.128/25
F – 172.17.10.0/24

Answer: C E F

Explanation

First, we should notice about the entry in the orange box, it shows that the network 172.17.10.0/24 is directly connected with this router and has a FD of 28160. So we can guess the networks that directly connected with router at 172.17.10.2 will be shown with an AD of 28160. From that, we find out 3 networks which are directly connected to the router at 172.17.10.2 (they are green underlined). The network 172.17.10.0/24 is surely directly connected to the router at 172.17.10.2 (in fact it is the network that links the router at 172.17.10.2 with Core1 router).

Question 1

Which three descriptions are correct based on the exhibited output? (Choose three)

A. R1 is configured with the variance command.
B. The route to 10.2.0.0/16 was redistributed into EIGRP.
C. A default route has been redistributed into the EIGRP autonomous system.
D. R1 is configured with the ip summary-address command.

Answer: A C D

Explanation

From the routing table above, we see that network 172.16.1. can be reached via 2 unequal paths (with FD of 23072000 & 20640000) so surely R1 has been configured with the “variance” command -> A is correct.

By configuring a default route and redistribute it into EIGRP you will get the line “D *EX 0.0.0.0/0 …” line in the routing table of that router -> C is correct.

From the line “10.2.0.0/16 is a summary, 00:16:18, Null0″ we know that this network has been summarized with the “ip summaray-address” command (notice that 10.2.0.0 is not the major network of net-> D is correct.

Question 2

Refer to the exhibit. Which two statements are true? (Choose two)

A. The eigrp stub command prevents queries from being sent from R2 to R1.
B. The eigrp stub command will automatically enable summarization of routes on R2.
C. The eigrp stub command prevents all routes except a default route from being advertised to R1.
D. Router R1 will advertise connected and summary routes only.
E. Router R1 will advertise connected and static routes. The sending of summary routes will not be permitted.
F. Router R1 is configured as a receive-only neighbor and will not send any connected, static or summary routes.

Answer: A D

Explanation

The command “eigrp stub” turns R1 into a stub router so R2 will never send any query to R1 because R2 knows that a stub router will only route packets for networks it has explicitly advertised -> A is correct.

The command “eigrp stub” is same as “eigrp stub connected summary” command because connected and summarized routes are advertised by default -> D is correct.

Note: Because the network 192.168.50.0 is not advertised by “network” statement, it is necessary to redistribute connected route with the “redistribute connected” command.

Question 3

Refer to the exhibits. Router B should advertise the network connected to the E0/0/0 interface to router A and block all other network advertisements. The IP routing table on router A indicates that it is not receiving this prefix from router B.
What is the probable cause of the problem?

A. An access list on router B is causing the 192.168.3.16/28 network to be denied.
B. An access list on router B is causing the 192.168.3.32/28 network to be denied.
C. The distribute list on router B is referencing a numbered access list that does not exist on router B.
D. The distribute list on router B is referencing the wrong interface.

Answer: A

Explanation

This is an unclear question. The question says “Router B should advertise the network connected to the E0/0/0 interface to router A and block all other network advertisements. The IP routing table on router A indicates that it is not receiving this prefix from router B.” That means the network 192.168.3.16/28 (including the IP 192.168.3.21/28) is not received on router A -> A is the most suitable answer.

Note: Distribute list are used to filter routing updates and they are based on access lists.

Question 4

Study the exhibit carefully. What must be done on router A in order to make EIGRP work effectively in a Frame Relay multipoint environment?

A. Issue the command bandwidth 56 on the physical interface.
B. Issue the command bandwidth 56 on each subinterface.
C. Issue the command bandwidth 224 on each subinterface.
D. Issue the command bandwidth 224 on the physical interface.

Answer: D

Explanation

In Frame Relay, all neighbors share the same bandwidth, regardless of the actual CIR of each individual PVC. In this case the CIR of each PVC is the same so we can find the bandwidth of the main interface (multipoint connection interface) by 56 x 4 = 224.

Notice that if the bandwidth on each PVC is not equal then we get the lowest bandwidth to multiply.

Question 5

Refer to the exhibit. ROUTE Enterprises has many stub networks in their enterprise network, such as router B and its associated network. EIGRP is to be implemented on router A so that neither the prefix for the S/0/0/0 interface nor the prefixes from router B appear in the routing tables for the router in the enterprise network.
Which action will accomplish this goal?

A. Declare router B a stub router using the eigrp stub command.
B. Use the passive-interface command for interface Serial0/0/0.
C. Use a mask with the network command to exclude interface Serial0/0/0.
D. Implement a distribute list to exclude the link prefix from the routing updates.

Answer: C

Explanation

If we declare router B a stub router then the routers in Enterprise Network still learn about the network for S0/0/0 interface and the network behind router B -> A is not correct.

If we use the passive-interface command on s0/0/0 interface then router A & B can not become neighbor because they don’t exchange hello messages -> A can not send traffic to the network behind B -> B is not correct.

Theoretically, we can use a distribute list to exclude both the link prefix and the prefix from router B but it is not efficient because:

+ We have many stub networks so we will need a “long” distribute list.
+ We declare networks in stub routers (like router B) while filter them out at router A -> it is a waste.

I am not totally sure about answer C because if we “use a mask with the network command to exclude interface Serial0/0/0″ then router A and B can not become neighbors and the situation is same as answer B. But from many discussions about this question, maybe C is the best answer.

Question 6

Refer to the exhibit. EIGRP is configured with the default configuration on all routers. Autosummarization is enabled on routers R2 and R3, but it is disabled on router R1. Which two EIGRP routes will be seen in the routing table of router R3? (Choose two)

A. 10.0.0.0/8
B. 10.10.0.0/16
C. 10.10.10.0/24
D. 172.16.0.0/16
E. 172.16.0.0/24
F. 172.16.10.0/24

Answer: C D

Explanation

EIGRP performs an auto-summarization each time it crosses a border between two different major networks. In this case all different networks are in different major networks so EIGRP will perform auto-summarization when it exits an interface. But R1 has been configured with “no auto-summary” command so EIGRP will not summarize on S0 interface of R1. So the routing table of R2 will have the network 10.10.10.0/24 (not be summarized).

When exiting S1 interface of R2, EIGRP summarizes network 172.16.10.0/24 into the major 172.16.0.0/16 network but it does not summarize network 10.10.10.0/24 because it is not directly connected with this network. Therefore in the routing table of R3 there will have:

+ Network 10.10.10.0/24 ( not summarized)
+ Network 172.16.0.0/16 (summarized)

-> C and D are correct.

Note: I simulated this question on GNS3, you can see the final outputs of the “show ip route” commands on these routers (I connected these routers via FastEthernet, not Serial interfaces so the outputs are slightly different but the main points are not changed).

Question 7

Refer to the exhibit. In a redundant hub-and-spoke deployment using EIGRP, what feature can be used to ensure that routers C through F are not used as transit routers for data traveling from router B to network 10.1.1.0?

A. Use address summarization at routers C, D. E, and F.
B. Use the EIGRP Stub feature on routers C, D, E, and F.
C. Use passive-interface on the spoke links in routers A and B.
D. Change the administrative distance in routers A and B for routes learned from routers Cr D. E, and F.

Answer: B

Explanation

By configuring “stub” feature on routers C D E and F, routers A and B will not try to transit traffic through these routers. For example, if the network connecting from routers A and B is down, router B will not send to network 10.1.1.0/24 from router B -> routerC/D/E/F -> router A -> network 10.1.1.0/24.

Question 8

Refer to the exhibit. How would you confirm on R1 that load balancing is actually occurring on the default-network (0.0.0.0)?

A. Use ping and the show ip route command to confirm the timers for each default network resets to 0.
B. Load balancing does not occur over default networks; the second route will only be used for failover.
C. Use an extended ping along with repeated show ip route commands to confirm the gateway of last resort address toggles back and forth.
D. Use the traceroute command to an address that is not explicitly in the routing table.

Answer: D

Explanation

The most simple method to test load balancing is to use the “traceroute” command. If load balancing is working correctly, we will see different paths to reach the destination each time we use that command.

Unknown address will be routed via the default-network 0.0.0.0 so we must use an address that is not explicitly in the routing table.

Question 9

Refer to the exhibit. ROUTE.com is planning to implement load balancing for traffic between host on the 172.16.10.0/24 and 172.16.20./24 networks. You have been asked to review the implementation plan for this project. Which statement about the plan is true?

A. It is complete as written.
B. It should include a task to configure EIGRP multipath equal to 2 on R1 and R4.
C. It should include a task to implement OSPF because it handles unequal cost load balancing most efficiently using variance.
D. It should include a task that establishes a baseline before and after the configuration has been changed.

Answer: D

Explanation

A complete implementation plan should be:

1. Configure variance on R1 and R4
2. Use traceroute to validate load balancing has been activated
3. Document configuration changes
4. Establish a new traffic throughput baseline
5. Compare the new and old baselines and verify that load balancing is implemented as desired.

Question 10

Refer to the exhibit. ROUTE.com is planning to implement load balancing for traffic between host on the 172.16.10.0/24 and 172.16.20./24 networks. You have been asked to review the implementation plan for this project. Which statement about the plan is true?

A. It is complete as written.
B. It should include a task to configure multipath to equal a value of 2 on R1 and R4.
C. It should use a ping instead of a traceroute to validate that load balancing has been activated.
D. It should contain a task that documents the changes made to the configurations.

Answer: D

Explanation

Same as questions 9

Question 11

Refer to the exhibit. EIGRP had converged in AS 1 when the link between router R1 and R2 went down. The console on router R2 generated the following messages:

*Mar 20 12:12:06: %DUAL-5-NBRCHANGE: IP-EIGRP 1: Neighbor 10.1.4.3 (Serial0) is down: stuck in active *Mar 20 12:15:23: %DUAL-3-SIA: Route 10.1.1.0/24 stuck-in-active state in IP-EIGRP 1. Cleaning up

The network administrator issued the show ip eigrp topology active command on R2 to check the status of the EIGRP network. Which statement best describes the reason for the error messages?

A. Incorrect bandwidth configuration on router R3 prevents R2 from establishing neighbor adjacency.
B. Incorrect bandwidth configuration on router R5 prevents R2 from establishing neighbor adjacency.
C. Router R3 did not reply to the query about network 10.1.1.0/24 sent by router R2.
D. Router R5 did not reply to the query about network 10.1.1.0/24 sent by router R2.

Answer: C

Explanation

When the link between R1 and R2 is down, R2 loses its successor for the network 10.1.1.0/24. R2 checks its topology table for a feasible successor but it can’t find one. So R2 goes active on the that route to find a new successor by sending queries out to its neighbors (R3 and R5) requesting a path to the lost route. Both R3 and R5 also go “active” for the that route. But R5 doesn’t have any neighbor to ask besides R2 so it will send an “unreachable message” to indicate it has no alternative path for that route and has no other neighbor to query. R3 also checks its EIRGP topology table for a feasible successor but it has none, too. Unlike R5, R3 has a neighbor (R4) so it continues to query this router.

Now suppose there is a problem on the link between R3 and R4 so R4 never receives the query from R3 and of course, R3 also never receives a reply back from R4. Therefore, R3 can’t reply back to R2. After about 3 minutes, the “Stuck in active” (SIA) timer on R2 expires and R2 marks the route 10.1.1.0/24 as “stuck in active” route.

The output line “via 10.1.3.3 (Infinity/Infinity), r, Seiral0, serno 1232″ indicates R2 has sent a query to 10.1.3.3 and is waiting for a reply (the lowercase r) -> C is correct.

(Reference: http://www.cisco.com/en/US/tech/tk365/technologies_tech_note09186a008010f016.shtml)

Question 12

Refer to the exhibit. EIGRP has been configured on routers R1 and R2. However, R1 does not show R2 as a neighbor and does not accept routing updates from R2. What could be the cause of the problem?

A. The no auto-summary command has not been issued under the EIGRP process on both routers.
B. Interface E0 on router R1 has not been configured with a secondary IP address of 10.1.2.1/24.
C. EIGRP cannot exchange routing updates with a neighbor’s router interface that is configured with two IP addresses.
D. EIGRP cannot form neighbor relationship and exchange routing updates with a secondary address.

Answer: D

Explanation

EIGRP updates always use the primary IP address of the outgoing interface as the source address. In this case R2 will use the 10.1.2.2/24 address, which is not in the same subnet of R1, to send EIGRP update to R1. Therefore R1 does not accept this update and generates the “not on common subnet” error message.

Answer D is a bit unclear. It should state that “EIGRP cannot form neighbor relationship and exchange routing updates if the two primary addresses on two routers are not in the same subnet”.

Notice that although R1 does not accept R2 as its EIGRP neighbors but R2 accepts R1 as its EIGRP neighbor accepts R1 hello packets..

For more information about this problem, please readhttp://www.cisco.com/en/US/tech/tk365/technologies_configuration_example09186a0080093f09.shtml.

Question 13

Refer to the exhibit. A Boston company bought the assets of a New York company and is trying to route traffic between the two data networks using EIGRP over EoMPLS. As a network consultant, you were asked to verify the interoperability of the two networks.

From the show ip route command output, what can you tell the customer about the traffic flow between the subnet in New York (172.16.8.0/24) and the subnets in Boston (172.16.16.0/24 and 10.10.16.0/24)?

A. Traffic is flowing between the 172.16.8.0 subnet and subnets 172.16.16.0 and 10.10.16.0 and no configuration changes are needed.
B. Auto-summary must be disabled on N1 and B1 before traffic can flow between the 172.16.8.0 subnet and subnets 172.16.16.0 and 10.10.16.0.
C. Traffic will flow between the 172.16.8.0 subnet and 172.16.16.0 without any further configuration changes. However, auto-summary must be disabled on N1 and B1 before traffic can flow between the 172.16.8.0 subnet and the 10.10.16.0 subnet.
D. Auto-summary must be disabled on N1 and B1 before traffic can flow between the 172.16.8.0 subnet and the 172.16.16.0 subnet. However, traffic will flow between the 172.16.8.0 subnet and 10.10.16.0 without any further configuration changes.

Answer: B

Question 14

Refer to the exhibit. A Boston company bought the assets of a New York company and is trying to route traffic between the two data networks using EIGRP. The show command output shows that traffic will not flow between the networks. As a network consultant, you were asked to modify the configuration and certify the interoperability of the two networks. For traffic to flow from subnet 172.16.8.0/24 to the 172.16.16.0/24 subnet, which configuration change do you recommend?

A. Turn off autosummarization on routers N1 and B1.
B. Add IP summary addresses to the Internet-pointing interfaces of routers N1 and B1.
C. Turn off autosummarization on routers N2 and B2.
D. Add wildcard masks to the network commands on routers N2 and B2.

Answer: A

Question 1

Which three statements are true about EIGRP route summarization? (Choose three)

A. Manual route summarization is configured in router configuration mode when the router is configured for EIGRP routing.
B. Manual route summarization is configured on the interface.
C. When manual summarization is configured, the summary route will use the metric of the largest specific metric of the summary routes.
D. The ip summary-address eigrp command generates a default route with an administrative distance of 90.
E. The ip summary-address eigrp command generates a default route with an administrative distance of 5.
F. When manual summarization is configured, the router immediately creates a route that points to null0 interface

Answer: B E F

Explanation

The ip summary-address eigrp {AS number} {address mask} command is used to configure a summary aggregate address for a specified interface. For example with the topology below:

R2 has 5 loopback interfaces but instead of advertising all these interfaces we can only advertise its summarized subnet. In this case the best summarized subnet should be 1.1.1.0/29 which includes all these 5 loopback interfaces.

R2(config)#interface fa0/0
R2(config-if)#ip summary-address eigrp 1 1.1.1.0 255.255.255.248

This configuration causes EIGRP to summarize network 1.1.1.0 and sends out Fa0/0 interface

After configuring manual EIGRP summary, the routing table of the local router will have a route to Null0:

So why is this route inserted in the routing table when doing summarization? Well, you may notice that although our summarized subnet is 1.1.1.0/29 but we don’t have all IP addresses in this subnet. Assignable IP addresses of subnet 1.1.1.0/29 are from 1.1.1.1 to 1.1.1.6. Imagine what happens if R1 sends a packet to 1.1.1.6. Because R1 do believe R2 is connected with this IP so it will send this packet to R2. But R2 does not have this IP so if R2 has a default-route to R1 (for example R1 is connected to the Internet and R2 routes all unknown destination IP packets to R1) then a loop will occur.

To solve this problem, some routing protocols automatically add a route to Null0. A packet is sent to “Null0″ means that packet is dropped. Suppose that R1 sends a packet to 1.1.1.6 through R2, even R2 does not have a specific route for that IP, it does have a general route pointing to Null0 which the packet sent to 1.1.1.6 can be matched -> That packet is dropped at R2 without causing a routing loop!

By default, EIGRP summary routes are given an administrative distance value of 5. Notice that this value is only shown on the local router doing the summarization. On other routers we can still see an administrative distance of 90 in their routing table.

Question 2

After implementing EIGRP on your network, you issue the show ip eigrp traffic command on router C. The following output is shown:

RouterC#show ip eigrp traffic
IF-EIGRP Traffic Statistics for process 1
Hellos sent/received: 481/444
Updates sent/received: 41/32
Queries sent/received: 5/1
Replies sent/received: 1/4
Acks sent/received: 21/25
Input queue high water mark 2, 0 drops
SIA-Queries sent/received: 0/0
SIA-Replies sent/received: 0/0

Approximately 25 minutes later, you issue the same command again. The following output is shown:

RouterC#show ip eigrp traffic
IP-EIGRP Traffic Statistics for process 1
Hellos sent/received: 1057/1020
Updates sent/received: 41/32
Queries sent/received: 5/1
Replies sent/received: 1/4
Acks sent/received: 21/25
Input queue high water mark 2, 0 drops
SIA-Queries sent/received: 0/0
SIA-Replies sent/received: 0/0

Approximately 25 minutes later, you issue the same command a third time. The following output is shown:

RouterC#show ip eigrp traffic
IP-EIGRP Traffic Statistics for process 1
Hellos sent/received: 1754/1717
Updates sent/received: 41/32
Queries sent/received: 5/1
Replies sent/received: 1/4
Acks sent/received: 21/25
Input queue high water mark 2, 0 drops
SIA-Queries sent/received: 0/0
SIA-Replies sent/received: 0/0

What can you conclude about this network?

A. The network has been stable for at least the last 45 minutes.
B. There is a flapping link or interface, and router C knows an alternate path to the network.
C. There is a flapping link or interface, and router A does not know an alternate path to the network.
D. EIGRP is not working correctly on router C.
E. There is not enough information to make a determination.

Answer: A

Explanation

In three times using the command, the “Queries sent/received” & “Replies sent/received” are still the same -> the network is stable.

Question 3

After implementing EIGRP on your network, you issue the show ip eigrp traffic command on router C. The following output is shown:

RouterC#show ip eigrp traffic
IP-EIGRP Traffic Statistics for process 1
Hellos sent/received: 2112/2076
Updates sent/received: 47/38
Queries sent/received: 5/3
Replies sent/received: 3/4
Acks sent/received: 29/33
Input queue high water mark 2, 0 drops
SIA-Queries sent/received: 0/0
SIA-Replies sent/received: 0/0

Moments later, you issue the same command a second time and the following output is shown:

RouterC#show ip eigrp traffic
IP-EIGRP Traffic Statistics for process 1
Hellos sent/received: 2139/2104
Updates sent/received: 50/39
Queries sent/received: 5/4
Replies sent/received: 4/4
Acks sent/received: 31/37
Input queue high water mark 2, 0 drops
SIA-Queries sent/received: 0/0
SIA-Replies sent/received: 0/0

Moments later, you issue the same command a third time and the following output is shown:

RouterC#show ip eigrp traffic
IP-EIGRP Traffic Statistics for process 1
Hellos sent/received: 2162/2126
Updates sent/received: 53/42
Queries sent/received: 5/5
Replies sent/received: 5/4
Acks sent/received: 35/41
Input queue high water mark 2, 0 drops
SIA-Queries sent/received: 0/0
SIA-Replies sent/received: 0/0

What information can you determine about this network?

A. The network is stable.
B. There is a flapping link or interface, and router C knows an alternate path to the network.
C. There is a flapping link or interface, and router C does not know an alternate path to the network.
D. EIGRP is not working correctly on router C.
E. There is not enough information to make a determination.

Answer: B

Explanation

We notice that the “Queries received” number is increased so router C has been asked for a route. The “Replies sent” number is also increased -> router C knows an alternate path to the network.

Question 4

R1 and R2 are connected and are running EIGRP on all their interfaces, R1 has four interfaces, with IP address 172.16.1.1/24, 172.16.2.3/24,172.16.5.1/24, and 10.1.1.1/24. R2 has two interfaces, with IP address 172.16.1.2/24 and 192.168.1.1/24. There are other routers in the network that are connected on each of the interfaces of these two routers that are also running EIGRP. Which summary routes does R1 generate automatically (assuming auto-summarization is enable)? (choose two)

A. 192.168.1.0/24
B. 10.0.0.0/8
C. 172.16.1.0/22
D. 172.16.0.0/16
E. 10.1.1.0/24

Answer: B D

Question 5

There was an exhibit, 172.16.1.0/24 to 172.16.2.0/24 with the 4 paths with mentions of eigrp metric and asked if the variance is put to 2 in exhibit then what 2 paths are not used by eigrp routing table? (Choose two)

A. R1—R2—R6
B. R1—R3—R6
C. R1—R4—R6
D. R1—R5—R6

Answer: C D

Question 6

What does the default value of the EIGRP variance command of 1 mean?

A. Load balancing is disabled on this router.
B. The router performs equal-cost load balancing.
C. Only the path that is the feasible successor should be used.
D. The router only performs equal-cost load balancing on all paths that have a metric greater than 1.

Answer: B

Question 7

Refer to the exhibit. EIGRP has been configured on all routers in the network. The command metric weights 0 0 1 0 0 has been added to the EIGRP process so that only the delay metric is used in the path calculations. Which router will R1 select as the successor and feasible successor for Network A?

A. R4 becomes the successor for Network A and will be placed in the routing table. R2 becomes the feasible successor for Network A.
B. R4 becomes the successor for Network A and will be included in the routing table. No feasible successor will be selected as the advertised distance from R2 is higher than the feasible distance.
C. R2 becomes the successor and will be placed in the routing table. R4 becomes the feasible successor for Network A.
D. R2 becomes the successor and will be placed in the routing table. No feasible successor will be selected as the reported distance from R4 is lower than the feasible distance.

Answer: B

Question 8

Based on the exhibited output, which three statements are true? (Choose three)

A. R1 is in AS 200.
B. R1 will load balance between three paths to reach the 192.168.1.48/28 prefix because all three paths have the same advertised distance (AD) of 40512000.
C. The best path for R1 to reach the 192.168.1.48/28 prefix is via 192.168.1.66.
D. 40512000 is the advertised distance (AD) via 192.168.1.66 to reach the 192.168.1.48/28 prefix.
E. All the routes are in the passive mode because these routes are in the hold-down state.
F. All the routes are in the passive mode because R1 is in the query process for those routes.

Answer: A C D

Explanation

In the statement “IP-EIGRP Topology Table for process 200″, process 200 here means AS 200 -> A is correct.

There are 3 paths to reach network 192.168.1.48/28 but there is only 1 path in the routing table (because there is only 1 successor) so the path with least FD will be chosen -> path via 192.168.1.66 with a FD of 40537600 will be chosen -> C is correct.

The other parameter, 40512000, is the AD of that route -> D is correct.

Question 9

Characteristics of the routing protocol EIGRP? (choose two)

A. Updates are sent as broadcast.
B. Updates are sent as multicast.
C. LSAs are sent to adjacent neighbors.
D. Metric values are represented in a 32-bit format for granularity.

Answer: B D

Question 10

Which EIGRP packet statement is true?

A. On high-speed links, hello packets are broadcast every 5 seconds for neighbor discovery.
B. On low-speed links, hello packets are broadcast every 15 seconds for neighbor discovery.
C. Reply packets are multicast to IP address 224.0.0.10 using RTP.
D. Update packets route reliable change information only to the affected routers.
E. Reply packets are used to send routing updates.

Answer: D

Question 1

Refer to the exhibit. ROUTE.com has just implemented this EIGRP network. A network administrator came to you for advice while trying to implement load balancing across part of their EIGRP network.
If the variance value is configured as 2 on all routers and all other metric and K values are configured to their default values, traffic from the Internet to the data center will be load balanced across how many paths?

A. 1

B. 2
C. 3
D. 4

Answer: C

Explanation

First we should list all the paths from the Internet to the data center:

+ A-B-C-H with a metric of 70 (40 + 15 + 15)
+ A-B-E-H with a metric of 60 (40+10+10)
+ A-D-E-H with a metric of 30 (10+10+10)
+ A-D-E-B-C-H with a metric of 60 (10+10+10+15+15)
+ A-D-E-F-G-H with a metric of 70 (10+10+10+20+20)
+ A-F-G-H with a metric of 60 (20+20+20)
+ A-F-E-H with a metric of 40 (20+10+10)

So the path A-D-E-H will be chosen because it has the best metric. But EIGRP can support unequal cost path load balancing. By configuring the variance value of 2, the minimum metric is increased to 60 (30 * 2) and all the routes that have a metric of less than or equal to 60 and satisfy the feasibility condition will be used to send traffic.

Besides the main path A-D-E-H we have 4 more paths that have the metric of less than or equal to 60 (we also include the Advertised Distances of these routes for later comparison):

+ A-B-E-H with an AD of 20
+ A-D-E-B-C-H with an AD of 50
+ A-F-G-H with an AD of 40
+ A-F-E-H with an AD of 20

Now the last thing we need to consider is the feasible condition. The feasible condition states:

“To qualify as a feasible successor, a router must have an AD less than the FD of the current successor route”

The FD of the current successor route here is 30 (notice that the variance number is not calculated here). Therefore there are only 2 paths that can satisfy this conditions: the path A-B-E-H & A-F-E-H.

In conclusion, traffic from the Internet to the data center will be load balanced across 3 paths, including the main path (successor path) -> C is correct.

Question 2

Which condition must be satisfied before an EIGRP neighbor can be considered a feasible successor?

A. The neighbor’s advertised distance must be less than or equal to the feasible distance of the current successor. 
B. The neighbor’s advertised distance must be less than the feasible distance of the current successor. 
C. The neighbor’s advertised distance must be greater than the feasible distance of the current successor. 
D. The neighbor’s advertised distance must be equal to the feasible distance of the current successor. 
E. The neighbor’s advertised distance must be greater than or equal to the feasible distance of the current successor.

Answer: B

Explanation

As explained in question 1, this is called the feasible condition.

Question 3

Which statement about a non-zero value for the load metric (k2) for EIGRP is true?

A. A change in the load on an interface will cause EIGRP to recalculate the routing metrics and send a corresponding update out to each of its neighbors. 
B. EIGRP calculates interface load as a 5-minute exponentially weighted average that is updated every 5 minutes.
C. EIGRP considers the load of an interface only when sending an update for some other reason.
D. A change in the load on an interface will cause EIGRP to recalculate and update the administrative distance for all routes learned on that interface.

Answer: C

Explanation

The load metric (k2) represents the worst load on a link between source and destination.

EIGRP routing updates are triggered only by a change in network topology (like links, interfaces go up/down, router added/removed), and not by change in interface load or reliability -> A & D are not correct.

The load is a five minute exponentially weighted average that is updated every five seconds (not five minutes) -> B is not correct.

EIGRP considers the load of an interface only when sending an update for some other reason (like a link failure) -> C is correct.

Question 4

Your network consists of a large hub-and-spoke Frame Relay network with a CIR of 56 kb/s for each spoke.
Which statement about the selection of a dynamic protocol is true?

A. EIGRP would be appropriate if LMI type ANSI is NOT used.
B. EIGRP would be appropriate, because the Frame Relay spokes could be segmented into their own areas.
C. EIGRP would be appropriate, because by default, queries are not propagated across the slow speed Frame Relay links.
D. EIGRP would be appropriate, because you can manage how much bandwidth is consumed over the Frame Relay interface.

Answer: D

Explanation

By default, EIGRP will limit itself to using no more than 50% of the interface bandwidth. The primary benefit of controlling EIGRP’s bandwidth usage is to avoid losing EIGRP packets, which could occur when EIGRP generates data faster than the interface line can absorb it. This is of particular benefit on Frame Relay networks, where the access interface bandwidth and the PVC capacity may be very different.

For example, in our Frame Relay topology a Hub is connected with 4 Spoke routers. The main Frame Relay interface on Hub router is 512Kpbs which is not enough to use for 6 links of 128 Kbps ( = 768 Kbps).

The solution here is we can use 512 / 6 = 85 Kbps on each subinterface of Hub by using “bandwidth 85″ command. For example:

Hub(config)#interface Serial0/0.1 point-to-point
Hub(config-subif)#bandwidth 85

Also on Spoke routers we need to set this value. For example on Spoke1:

Spoke1(config)#interface Serial0/1.0 point-to-point
Spoke1(config-subif)#bandwidth 85

Notice that by default, EIGRP limits itself to use no more than 50% of the configured interface bandwidth. In this case EIGRP will not use more than 42.5 Kbps (50% of 85 Kbps).

(For more information about implementing EIGRP over Frame Relay, please readhttp://www.cisco.com/en/US/tech/tk365/technologies_tech_note09186a0080094063.shtml)

Question 5

When an EIGRP topology change is detected, what is the correct order of events when there is a FS?

A. 
The neighbor adjacency is deleted. 
The feasible route is used. 
DUAL is notified.
Remove all topology entries learned from that neighbor.

B. 
DUAL is notified.
Remove all topology entries learned from that neighbor. 
The neighbor adjacency is deleted. 
Routes enter the Active state and the feasible route is used.

C.
The neighbor adjacency is deleted.
Routes enter the Active state and the feasible route is used. 
DUAL is notified.
Remove all topology entries learned from that neighbor.

D. 
DUAL is notified.
The neighbor adjacency is deleted.
Remove all topology entries learned from that neighbor.
The feasible route is used.

Answer: D

Question 6

Refer to the exhibit. You want to use all the routes in the EIGRP topology for IP load balancing.

Which two EIGRP subcommands would you use to accomplish this goal? (Choose two)

A. traffic-share balanced
B. distance
C. maximum-paths 
D. default-network
E. variance

Answer: C E

Explanation

Notice that the “maximum-paths” command is used to share traffic to equal cost path while the “variance” command can share traffic to unequal cost path.

In the output above we learn that EIGRP is using 2 successors to send traffic. By using the “variance 2″ command we can share traffic to other feasible successor routes. But by default, EIGRP only shares traffic to 4 paths. So we need to use the “maximum-paths 6″ to make sure all of these routes are used.

Question 7

Refer to the exhibit. R1 accesses the Internet using E0/0. You have been asked to configure R1 so that a default route is generated to its downstream devices (191.0.0.1 and 192.0.0.1). Which commands would create this configuration?

A.
router eigrp 190
redistribute static
!
ip route 0.0.0.0 0.0.0.0 Null0

B. ip default-network 20.0.0.0

C. 
router eigrp 190
redistribute static
!
ip route 0.0.0.0 255.255.255.255 Null0

D. ip default-network 20.20.20.0

Answer: A

Question 8

Which command will display EIGRP packets sent and received, as well as statistics on hello packets, updates, queries, replies, and acknowledgments?

A. debug eigrp packets
B. show ip eigrp traffic
C. debug ip eigrp
D. show ip eigrp interfaces

Answer: B

Explanation

Below is the output of the “show ip eigrp traffic” command:

Question 9

Which three statements are true about EIGRP operation? (Choose three)

A. When summarization is configured, the router will also create a route to null 0.
B. The summary route remains in the route table, even if there are no more specific routes to the network.
C. Summarization is configured on a per-interface level.
D. The maximum metric for the specific routes is used as the metric for the summary route.
E. Automatic summarization across major network boundaries is enabled by default.

Answer: A C E

Question 10

Which two statements about the EIGRP DUAL process are correct? (Choose two)

A. An EIGRP route will go active if there are no successors or feasible successors in the EIGRP topology table.
B. An EIGRP route will go passive if there are no successors in the EIGRP topology table.
C. DUAL will trigger an EIGRP query process while placing the flapping routes in the holddown state.
D. A feasible successor in the EIGRP topology table can become the successor only after all the query requests have been replied to.
E. The stuck in active state is caused when the wait for the query replies have timed out.
F. EIGRP queries are sent during the loading state in the EIGRP neighbor establishment process.

Answer: A E

Question 11

What are three key concepts that apply when configuring the EIGRP stub routing feature in a hub and spoke network? (Choose three)

A. A hub router prevents routes from being advertised to the remote router.
B. Only remote routers are configured as stubs.
C. Stub routers are not queried for routes.
D. Spoke routers connected to hub routers answer the route queries for the stub router.
E. A stub router should have only EIGRP hub routers as neighbors.
F. EIGRP stub routing should be used on hub routers only.

Answer: B C E

Question 1

Refer to the exhibit. EIGRP has been configured on all routers in the network. What additional configuration statement should be included on router R4 to advertise a default route to its neighbors?

A. R4(config)#ip default-network 10.0.0.0

B. R4(config)#ip route 0.0.0.0 0.0.0.0 10.1.1.1
C. R4(config)#ip route 10.0.0.0 255.0.0.0 10.1.1.1
D. R4(config-router)# default-information originate

Answer: A

Explanation

The “ip default-network ” command will direct other routers to send its unknown traffic to this network. Other router (R1,R2,R3) will indicate this network as the “Gateway of last resort”.

There is another way to route unknown traffic to 10.1.1.0/24 network: create a static route using “ip route 0.0.0.0 0.0.0.0 10.1.1.2″ command then inject this route using the “network 0.0.0.0″ command, or using “redistribute static” command.

Note: In EIGRP, default routes cannot be directly injected (as they can in OSPF with the default-information originate command. Also, EIGRP does not have the “default-information originate” command).

Question 2

Refer to the exhibit. Router RTA is the hub router for routers RTB and RTC. The Frame Relay network is configured with EIGRP, and the entire network is in autonomous system 1. However, router RTB and RTC are not receiving each other’s routes. What is the solution?

A. Configure the auto summary command under router eigrp 1 on router RTA.
B. Issue the no ip split horizon command on router RTA.
C. Configure subinterfaces on the spoke routers and assign different IP address subnets for each subinterface.
D. Check and change the access lists on router RTA.
E. Issue the no ip split horizon eigrp 1 command on router RTA.

Answer: E

Explanation

RTB and RTC cannot see each other because of the split horizon rule: “A router never sends information about a route back in same direction which is original information came”. To overcome this problem we can configure subinterfaces or disable split horizon with the command “no ip split horizon eigrp 1″ on RTA.

Question 3

When troubleshooting an EIGRP connectivity problem, you notice that two connected EIGRP routers are not becoming EIGRP neighbors. A ping between the two routers was successful. What is the next thing that should be checked?

A. Verify that the EIGRP hello and hold timers match exactly.
B. Verify that EIGRP broadcast packets are not being dropped between the two routers with the show ip EIGRP peer command. 
C. Verify that EIGRP broadcast packets are not being dropped between the two routers with the show ip EIGRP traffic command. 
D. Verify that EIGRP is enabled for the appropriate networks on the local and neighboring router.

Answer: D

Question 4

Refer to the exhibit. You are the network administrator of the Route.com company. You have been tasked to implement a hub and spoke EIGRP topology over Frame Relay to provide connectivity between the networks at headquarters and all 300 spokes.

Before you begin the actual implementation, which three pieces of information are more important to know than the others? (Choose three)

A. the Committed Information Rate of all the Frame Relay PVCs
B. the Cisco IOS version running on all the routers
C. the router model number of all the spoke routers
D. the number of HQ networks connected behind the headquarter routers
E. the routing policy, such as whether or not the spokes can be used as backup transient point between the two headquarter routers

Answer: A B E

Question 5

Refer to the exhibit. The Route.com company is running EIGRP between all the routers. Currently, if one of the LAN links (LAN1 or LAN2) at the headquarters flaps (goes up and down), the HQ-RTR1 and HQ-RTR2 routers will experience high CPU usage and have a long EIGRP convergence time. As the new network administrator, you are asked to investigate this situation and determine if there is a quick way to resolve this issue.

Which is the most important thing that you can quickly verify first to resolve this issue?

A. Verify that the bandwidth setting on all WAN links is correct.
B. Verify that the HQ-RTR1 and HQ-RTR2 routers are configured to send only a default route to all the spoke routers. 
C. Verify that the HQ-RTR1 and HQ-RTR2 routers are configured for EIGRP Nonstop Forwarding. 
D. Verify that all the spoke routers are configured for autosummarization. 
E. Verify that all the spoke routers are configured as EIGRP stub.

Answer: E

Question 6

Refer to the exhibit. When you examine the routing table of R1 and R4, you are not able to see the R1 Ethernet subnet on the R4 routing table. You are also not able to see the R4 Ethernet subnet on the R1 routing table.

Which configuration change should be made to resolve this issue? Select the routers where the configuration change will be required, and select the required EIGRP configuration command(s). (Choose two)

A. R1 and R4
B. R2 and R3
C. ip summary-address eigrp 1 10.1.1.0 255.255.255.0 and ip summary-address eigrp 1
D. variance 2
E. eigrp stub connected
F. no auto-summary

Answer: B F

Question 7

Refer to the exhibit. The actual speed of the serial links between R2 and R3 are 256 kb/s and 512 kb/s respectively. When configuring EIGRP on routers R2 and R3, the network administrator configured the bandwidth of both serial interfaces to 512 kb/s. What will be the effect?

A. EIGRP will overutilize the 512 kb/s link.
B. The interface “delay” value used in the EIGRP metric calculation will be inaccurate on the 256 kb/s serial interface.
C. The amount of bandwidth used for EIGRP routing protocol traffic on the 256 kb/s link can become excessive.
D. EIGRP can load balance between the two serial links only if the variance is set to 2 or higher.
E. Unequal cost load balancing will be disabled.

Answer: C

Question 1

Refer to the exhibit. Which statement is true?

hostname RAR1  ! <output omitted> ! router bgp 100  neighbor 172.16.1.2 remote-as 200  neighbor 172.16.1.2 distribute-list 101 in ! access-list 101 permit ip 10.10.0.0 0.0.0.0 255.255.224.0 0.0.0.0

A. Router RAR1 will accept only route 10.10.0.0/19 from its

BGP neighbor.
B. Router RAR1 will send only route 10.10.0.0/19 to its BGP neighbor.
C. Only traffic with a destination from 10.10.0.0/19 will be permitted.
D. Only traffic going to 10.10.0.0/19 will be permitted.

Answer: A

Question 2

Refer to the exhibit. Which three statements accurately describe the result of applying the exhibited route map? (Choose three)

router eigrp 1  redistribute ospf 1 route-map ospf-to-eigrp  default-metric 20000 2000 255 1 1500 ! ! route-map ospf-to-eigrp deny 10  match tag 6 match route-type external type-2 ! route-map ospf-to-eigrp permit 20  match ip address prefix-list pfx  set metric 40000 1000 255 1 1500 ! route-map ospf-to-eigrp permit 30  set tag 8

A. The map prohibits the redistribution of all type 2 external OSPF routes with tag 6 set.
B. The map prohibits the redistribution of all type 2 external OSPF routes.
C. The map redistributes into EIGRP all routes that match the pfx prefix list and the five metric values 40000, 1000, 255, 1, and 1500. 
D. The map prohibits the redistribution of all external OSPF routes with tag 6 set.
E. All routes that do no match clauses 10 and 20 of the route map are redistributed with their tags set to 8.
F. The map permits the redistribution of all type 1 external OSPF routes.

Answer: A E F

Explanation

In the route-map:

route-map ospf-to-eigrp deny 10 
match tag 6
match route-type external type-2

The deny clause rejects route matches from redistribution. If several match commands are present in a clause, all must succeed for a given route in order for that route to match the clause (in other words, the logical AND algorithm is applied for multiple match commands). In this question, both the “match tag 6″ and “match route-type external type-2″ must be matched for this route to be denied -> A is correct.

If a match command is not present, all routes match the clause. In this question, all routes that reach clause 30 match and their tags are set to 8 -> E is correct.

If a route is not matched with clause 10 or 20 then it will be matched with clause 30 for sure -> F is correct.

Note: Route-maps that are applied to redistribution behave the same way as ACLs: if the route does not match any clause in a route-map then the route redistribution is denied, as if the route-map contained deny statement at the end.

(Reference: http://www.cisco.com/en/US/tech/tk365/technologies_tech_note09186a008047915d.shtml)

Question 3

Refer to the exhibit. On the basis of the information in the exhibit, which two statements are true? (Choose two)

A. The output was generated by entering the show ip bgp command on the ISP router.
B. The output was generated by entering the show ip bgp command on the SanJose1 router.
C. The serial0/0/1 interface on the ISP router has been configured with the set metric 50 command.
D. The serial 0/0/1 Interface on the ISP router has been configured with the set metric 75 command.
E. When traffic is sent from the ISP to autonomous system 64512, the traffic will be forwarded to SanJose1 because of the lower MED value of SanJose1.
F. When traffic is sent from the ISP to autonomous system 64512, the traffic will be forwarded to SanJose2 because of the higher MED value of SanJose2.

Answer: A E

Explanation

From the output, we notice that the “local router ID” is 192.168.100.1 which is an interface on ISP router -> A is correct.

The show ip bgp command is used to display entries in the Border Gateway Protocol (BGP) routing table

Multi-Exit Discriminator (MED) is used when we have multiple entry points (connections) to another AS. A lower MED value is preferred over a higher value. Notice that the comparison between the MED only occurs if the first AS is the same in two (or more) paths. In this question, the first AS is 64512 which is the same -> the comparison can occur.

From the output, we learn that ISP router is receiving the 172.16.0.0 network from SanJose1 (192.168.1.6) with a metric of 50 and from SanJose2 (192.168.1.2) with a metric of 75. Also note that BGP has chosen the best path 192.168.1.6 to the 172.16.0.0 network (the “>” indicates it is the best path). The Weight, Local Preference (LocPrf) and AS-Path values between two next hops (192.168.1.2 & 192.168.1.6) are the same so we can deduce the traffic from ISP is sent from the ISP to SanJose1 because of the lower MED value.

Note: An entry of 0.0.0.0 in the “Next Hop” indicates that the router has some non-BGP routes to this network.

Question 4

Refer to the exhibit. Routers R1 and R2 have been configured to operate with OSPF. Routers R1 and R3 have been configured to operate with RIP. After configuring the redistribution between OSPF and RIP on R1, no OSPF routes are distributed into RIP. What should be done to correct this problem?

A. The redistribution command should be reentered with the match route-type parameter included. 
B. The redistribution command should be reentered with the route-map map-tag parameter included.
C. The redistribution command should be reentered with the metric metric-value parameter included. 
D. Routes will first need to be distributed into another protocol, and then into RIP.

Answer: C

Explanation

Notice that RIP metric is based on hop count only, and the maximum valid metric is 15. Anything above 15 is considered infinite. By default, when no metric is assigned when redistributing from EIGRP, OSPF, IS-IS, BGP into RIP, the default metric will be infinite. Therefore we must define a metric that is understandable to the receiving protocol. Usually, we should use a small value (like 1, 2, 3) so that after redistributing, that route can be advertised through many routers (because the limit is 15).

Question 5

router eigrp 123  redistribute ospf 123  network 116.16.35.0 0.0.0.255  network 130.130.0.0  auto-summary !  router ospf 123  log-adjacency-changes  network 116.16.34.0 0.0.0.255 area 0  neighbor 116.16.34.4

Refer to the exhibit. Why are the EIGRP neighbors for this router not learning the routes redistributed from OSPF?

A. Redistribution must be enabled mutually (in both directions) to work correctly.
B. Auto-summary causes the OSPF routes redistributed into EIGRP to be summarized; thus the OSPF network 116.16.34 is summarized to 116.34.0.0, which is already covered by the EIGRP protocol.
C. Default metrics are not configured under EIGRP.
D. Both routing protocols must have unique autonomous system numbers for redistribution to function correctly.

Answer: C

Explanation

Same as RIP, when redistribute into EIGRP from OSPF, the default metric is infinite -> We must set a seed metric when redistributing into EIGRP. Below lists the default seed metrics when redistributing from a routing protocol into another:

Redistributed Protocol	Default Seed Metric
RIP	Infinity
IGRP/EIGRP	Infinity
OSPF	20 for all (except for BGP, which is 1)
BGP	is set to IGP metric value

Question 6

If a metric is not specified for routes that are redistributed into OSPF, the default metric that is assigned to the routes is 20, except for redistributed BGP routes. What is the metric that is assigned to redistributed BGP routes?

A. 0
B. 1
C. 10
D. 200

Answer: B

Explanation

Same explanation of Question 5

Question 7

During a redistribution of routes from OSPF into EIGRP, an administrator notices that none of the OSPF routes are showing in EIGRP. What are two possible causes? (Choose two)

A. incorrect distribute lists have been configured 
B. missing ip classless command
C. CEF not enabled
D. no default metric configured for EIGRP

Answer: A D

Explanation

An incorrect distribute list can filter out updates therefore none of the OSPF routes are showing in EIGRP -> A is correct.

The default metric when redistributing into EIGRP is infinite so we must specify a seed metric for EIGRP to work with -> D is correct.

Question 8

During the redistribution process configured on RTA, some of the EIGRP routes, such as 10.1.1.0/24 and 10.2.2.0/24, are not being redistributed into the OSPF routing domain. Which two items could be a solution to this problem? (Choose two)

A. Change the metric-type to 2 in the redistribute command.
B. Configure the redistribute command under router eigrp 1 instead.
C. Change the EIGRP AS number from 100 to 1 in the redistribute command.
D. Add the subnets option to the redistribute command.
E. Change the metric to ah EIGRP compatible metric value (bandwidth, delay, reliability, load, MTUs) in the redistribute command.

Answer: C D

Explanation

The AS of EIGRP in the output above is not correct and we need to fix it into “eigrp 1″. Also, some of EIGRP routes, such as 10.1.1.0/24 and 10.2.2.0/24 are subnets so we must use the keyword “subnets” so that OSPF can see these routes. The full commands should be:

router ospf 1
redistribute eigrp 1 metric 20 metric-type 1 subnets

Question 9

You want the redistributed EIGRP AS 10 routes to have an administrative distance of 121 when they appear as RIP routes in the routing table of A1. Which command should you use on a router to accomplish this goal?

A. redistribute eigrp 10 metric 121
B. redistribute rip metric 121
C. default-metric 121
D. distance 121 10.1.1.6 0.0.0.0

Answer: D

Question 10

Refer to the exhibit. Which three commands should be used on router B1 to redistribute the EIGRP AS 10 routes into RIP? (Choose three)

A. router rip
B. router eigrp 10
C. redistribute eigrp 10 
D. redistribute rip
E. default-metric 10000 100 255 1 1500
F. default-metric 5

Answer: A C F

Following ticket consists of a problem description and existing configuration on the device.

TROUBLE TICKET STATEMENT:

The implementation group has been using the test bed to do a ‘proof-of-concept’ that required both client 1

and client 2 to access the Web Server at 209.65.200.241. After several changed to interface status,

network addressing, routing schemes and layer 2 connectivity, at trouble ticket has been opened indicating

that client 1 cannot ping the 209.65.200.241 (internet Server).

show run

Client 1 and Client 2 are getting a 169.x.x.x IP address and are not able to ping DSW1 or the FTP Server.

They are able to ping each other.

Configuration on R4

!

no ip domain lookup

ip dhcp excluded-address 10.2.1.1 10.2.1.253

ip dhcp excluded-address 10.2.1.254

!

ip dhcp pool TSHOOT network 10.2.1.0 255.255.255.0

default-router 10.2.1.254

!

The fault condition is related to which technology?

A. NTP

B. IP DHCP Server

C. IPv4 OSPF Routing

D. IPv4 EIGRP Routing

E. IPv4 Route Redistribution

F. IPv6 RIP Routing

G. IPv6 OSPF Routing

H. IPV4 and IPV6 Interoperability

I. IPV4 layer 3 security

Answer: B

Explanation/Reference:

Explanation:

Since Client1 is getting ip address 169.x.x.x, there may be problem in DHCP. On closer look into the DHCP

configuration on DHCP Server i.e R4 you get ip dhcp excluded-address command has wrongly configured.

So the fault condition is related to IP DHCP Server.

QUESTION 52

Following ticket consists of a problem description and existing configuration on the device.

TROUBLE TICKET STATEMENT:

The implementation group has been using the test bed to do a ‘proof-of-concept’ that required both client 1

and client 2 to access the Web Server at 209.65.200.241. After several changed to interface status,

network addressing, routing schemes and layer 2 connectivity, at trouble ticket has been opened indicating

that client 1 cannot ping the 209.65.200.241 (internet Server).

show run

Client 1 and Client 2 are getting a 169.x.x.x IP address and are not able to ping DSW1 or the FTP Server.

They are able to ping each other.

Configuration on R4

!

no ip domain lookup

ip dhcp excluded-address 10.2.1.1 10.2.1.253

ip dhcp excluded-address 10.2.1.254

!

ip dhcp pool TSHOOT

network 10.2.1.0 255.255.255.0

default-router 10.2.1.254

!

What is the soultion to the fault condition ?

A. Under global configuration, delete the no ip dhcp use vrf connected command.

B. Under IP DHCP pool configuration, delete the default-router 10.2.1.254 command and enter the default-

router 10.1.4.5 command.C. Under IP DHCP pool configuration, delete the network 10.2.1.0 255.255.255.0 command and enter the

network 10.1.4.0 255.255.255.0 command.

D. Under the IP DHCP pool configuration, issue the no ip dhcp excluded-address 10.2.1.1 10.2.1.253

command and enter the ip dhcp excluded-address 10.2.1.1 10.2.1.2 command.

Answer: D

Explanation/Reference:

Explanation:

Since Client1 is getting ip address 169.x.x.x, there may be problem in DHCP. On closer look into the DHCP

configuration on DHCP Server i.e R4 you get ip dhcp excluded-address command has wrongly configured.

Under IP DHCP pool configuration issue the command "no ip dhcp excluded-address 10.2.1.1

10.2.1.253" and enter the command " ip dhcp excluded-address 10.2.1.1 10.2.1.2". Soon the client 1 will

get the Ip address from DHCP.

QUESTION 53

Following ticket consists of a problem description and existing configuration on the device.

TROUBLE TICKET STATEMENT:

The implementation group has been using the test bed to do a ‘proof-of-concept’ that required both client 1

and client 2 to access the Web Server at 209.65.200.241. After several changed to interface status,

network addressing, routing schemes and layer 2 connectivity, at trouble ticket has been opened indicating

that client 1 cannot ping the 209.65.200.241 (internet Server).

show run

the neighborship between R4 and DSW1 wasn’t establised. Client 1 can’t ping R4

Configuration on R4

router eigrp 10

passive-interface default

redistribute ospf 1 route-map OSPF->EIGRP

network 10.1.4.4 0.0.0.3

network 10.1.4.8 0.0.0.3

default-metric 10000 100 255 1 10000

no auto-summary

On Which device is the fault condition located?

A. R1

B. R2

C. R3

D. R4

Answer: D

Explanation/Reference:

QUESTION 54

Following ticket consists of a problem description and existing configuration on the device.

TROUBLE TICKET STATEMENT:

The implementation group has been using the test bed to do a ‘proof-of-concept’ that required both client 1

and client 2 to access the Web Server at 209.65.200.241. After several changed to interface status,

network addressing, routing schemes and layer 2 connectivity, at trouble ticket has been opened indicatingthat client 1 cannot ping the 209.65.200.241 (internet Server).

show run

the neighborship between R4 and DSW1 wasn’t establised. Client 1 can’t ping R4

Configuration on R4

router eigrp 10

passive-interface default

redistribute ospf 1 route-map OSPF->EIGRP

network 10.1.4.4 0.0.0.3

network 10.1.4.8 0.0.0.3

default-metric 10000 100 255 1 10000

no auto-summary

The fault condition is related to which technology?

A. NTP

B. IP DHCP Server

C. IPv4 OSPF Routing

D. IPv4 EIGRP Routing

E. IPv4 Route Redistribution

F. IPv6 RIP Routing

G. IPv6 OSPF Routing

H. IPV4 and IPV6 Interoperability

I. IPV4 layer 3 security

Answer: D

Explanation/Reference:

QUESTION 55

Following ticket consists of a problem description and existing configuration on the device.

TROUBLE TICKET STATEMENT:

The implementation group has been using the test bed to do a ‘proof-of-concept’ that required both client 1

and client 2 to access the Web Server at 209.65.200.241. After several changed to interface status,

network addressing, routing schemes and layer 2 connectivity, at trouble ticket has been opened indicating

that client 1 cannot ping the 209.65.200.241 (internet Server).

show run

the neighborship between R4 and DSW1 wasn’t establised. Client 1 can’t ping R4

Configuration on R4

router eigrp 10

passive-interface default

redistribute ospf 1 route-map OSPF->EIGRP

network 10.1.4.4 0.0.0.3

network 10.1.4.8 0.0.0.3

default-metric 10000 100 255 1 10000

no auto-summary

What is the soultion to the fault condition ?

A. Remove “Passive interface” in Interface f0/1 and f0/0B.

C.

D.

Answer: A

Explanation/Reference:

QUESTION 56

The network setup for this trouble ticket is shown in Figure 3.

TROUBLE TICKET STATEMENT:

The implementation group has been using the test bed to do a ‘proof-of-concept’ that required both client 1

and client 2 to access the Web Server at 209.65.200.241. After several changed to interface status,

network addressing, routing schemes and layer 2 connectivity, at trouble ticket has been opened indicating

that client 1 cannot ping the 209.65.200.241 (internet Server).

show run

DSW1 and R4 cannot ping R2′s loopback or R2′s s0/0/0/0.12 IPv6 address. Initial troubleshooting shows

and R2 is not an OSPFv3 neighbor on R3.Configuration on R2:

ipv6 unicast-routing

!

ipv6 router ospf 6

router-id 2.2.2.2

!

interface s0/0/0/0.23

ipv6 address 2026::1:1/122

Configuration on R3

ipv6 unicast-routing

!

ipv6 router ospf 6

router-id 3.3.3.3

!

interface s0/0/0/0.23

ipv6 address 2026::1:2/122

ipv6 ospf 6 area 0

On Which device is the fault condition located?

A. DSW1

B. DSW2

C. R2

D. R3

Answer: C

Explanation/Reference:

Explanation:

Since both DSW1 and R4 cannot ping R2′s loopback or R2′s s0/0/0/0.12 interface we should start by

examining the configuration of R2. R2 is also not an IPv3 neighbor of R3. If you look at the configuration of

R2 you will notice that OSPFv3 has not been enabled on the connection to R3, confirming that the fault

condition is on R2.

QUESTION 57

The network setup for this trouble ticket is shown in Figure 3.

TROUBLE TICKET STATEMENT:

The implementation group has been using the test bed to do a ‘proof-of-concept’ that required both client 1

and client 2 to access the Web Server at 209.65.200.241. After several changed to interface status,

network addressing, routing schemes and layer 2 connectivity, at trouble ticket has been opened indicating

that client 1 cannot ping the 209.65.200.241 (internet Server).

show run

DSW1 and R4 cannot ping R2′s loopback or R2′s s0/0/0/0.12 IPv6 address. Initial troubleshooting shows

and R2 is not an OSPFv3 neighbor on R3.

Configuration on R2

ipv6 unicast-routing

!ipv6 router ospf 6

router-id 2.2.2.2

!

interface s0/0/0/0.23

ipv6 address 2026::1:1/122

Configuration on R3

ipv6 unicast-routing

!

ipv6 router ospf 6

router-id 3.3.3.3

!

interface s0/0/0/0.23

ipv6 address 2026::1:2/122

ipv6 ospf 6 area 0

The Fault Condition is related to which technology?

A. IPv6 Addressing

B. Route Redistribution

C. IPv6 OSPF Routing

D. RIPng

Answer: C

Explanation/Reference:

Explanation:

The key to this question is the fact there R3 has not formed an OSPFv3 neighbor relationship with R2 so

we can be fairly certain that the problem lies with the OSPFv3 configuration.

QUESTION 58

The network setup for this trouble ticket is shown in Figure 3.

TROUBLE TICKET STATEMENT:

The implementation group has been using the test bed to do a ‘proof-of-concept’ that required both client 1

and client 2 to access the Web Server at 209.65.200.241. After several changed to interface status,

network addressing, routing schemes and layer 2 connectivity, at trouble ticket has been opened indicating

that client 1 cannot ping the 209.65.200.241 (internet Server).

show run

DSW1 and R4 cannot ping R2′s loopback or R2′s s0/0/0/0.12 IPv6 address. Initial troubleshooting shows

and R2 is not an OSPFv3 neighbor on R3.

Configuration on R2

ipv6 unicast-routing

!

ipv6 router ospf 6

router-id 2.2.2.2

!

interface s0/0/0/0.23

ipv6 address 2026::1:1/122Configuration on R3

ipv6 unicast-routing

!

ipv6 router ospf 6

router-id 3.3.3.3

!

interface s0/0/0/0.23

ipv6 address 2026::1:2/122

ipv6 ospf 6 area 0

What is the solution of the fault condition?

A. Under the interface Serial 0/0/0.23 configuration enter the ipv6 ospf 6 area 0 command.

B. Add ipv6 ospf 6 area 6 under s0/0/0/0.23 on R2

C. Remove IPv6 address from s0/0/0/0.23 on R2

D. Enable IPv6 routing on s0/0/0/0.23 on R2

Answer: A

Explanation/Reference:

Explanation:

Unlike OSPF on IPv4 where networks are added under the routing process, IPv6 needs OSPFv3 enabled

on a per-interface basis. This has been done on the R3 connection to R2, but not on the R2 connection

back to R3. We will need to add the "ipv6 ospf 6 area 0" configuration command to the s0/0/0/0.23 interface

of R2